Query for webmaster (because Roger won't know)

[The Peepmaster]

Hang on. You ban me? Are we forgetting the natural order of things round here?  :

[Tarquin Thunderthighs lll]

I knew I was right to use the plural. 

[Mince]

Hang on. You ban me? Are we forgetting the natural order of things round here?  :

Are we forgetting my programming skills?

[The Peepmaster]

I wouldn't have a clue how the "back-end" of this site works, so you've more or less confessed. :

[Mince]

Good. Then once I have removed the censored words, it should stay that way.

[The Peepmaster]

Bum. Bugger.

It's not working.

[Fyodor]

I knew that.

Okay, try this puzzle (which I worked out in two hours at the age of fourteen).

Computers use bytes (eight bits) that can store any number between 0 and 255.

To store larger numbers, it uses more bytes.

Work out why each of these pairs of numbers represents the larger number.

10, 23 = 5898

101, 123 = 31589

123, 101 = 25979

143, 134 = 34447

Deep sigh!

The second number in each pair is the number of times the number is
divisible by 256, and the first number in the pair is the remainder.

so 5898 = 10 + (23 x 256)
31589 = 101 + (123 x 256)

so basically in 2 bytes (which can each take any value from 0 to 255),
you can store numbers in the format (byte1 x 256) +byte2

You can then store any number from 0 to 65025 (255x255) in 2 bytes

No further correspondence on this subject will be welcome, oleaginous, ophidian antecedents,  in particular.

[Tarquin Thunderthighs lll]

You sure?

[The Peepmaster]

 : has met his

[Mince]

Okay, try this puzzle (which I worked out in two hours at the age of fourteen).

Computers use bytes (eight bits) that can store any number between 0 and 255.

To store larger numbers, it uses more bytes.

Work out why each of these pairs of numbers represents the larger number.

10, 23 = 5898

101, 123 = 31589

123, 101 = 25979

143, 134 = 34447

Deep sigh!

The second number in each pair is the number of times the number is
divisible by 256, and the first number in the pair is the remainder.

so 5898 = 10 + (23 x 256)
31589 = 101 + (123 x 256)

so basically in 2 bytes (which can each take any value from 0 to 255),
you can store numbers in the format (byte1 x 256) +byte2

You can then store any number from 0 to 65025 (255x255) in 2 bytes

No further correspondence on this subject will be welcome, oleaginous, ophidian antecedents,  in particular.

Actually, the largest number that can be stored in two bytes is 255, 255 = 65535 (i.e. 255 + 255 x 256).

Apart from that, it's not bad.

[Tarquin Thunderthighs lll]

Maybe he's talking about economy bytes. 

[Colin]

The snooker is back on.
Stephen Hendry is winning.

[Mince]

Maybe he's talking about economy bytes. 

Well done for not getting the answer. Your manly image is returning.

[The Peepmaster]

Okay, my turn for a question:

"What's the difference between a pilchard, and Mince?"

[Vulture]

Okay, my turn for a question:

"What's the difference between a pilchard, and Mince?"

Pilchards are nice in a brown bread sandwich and Mince......